Question 25·Easy·Linear Equations in Two Variables
At a school fundraiser, bracelets cost $2 each and necklaces cost $5 each. The equation
represents the total amount of money, in dollars, collected from selling bracelets and necklaces. If necklaces are sold, how many bracelets are sold?
For SAT word problems that give a linear equation and then specify one variable, plug the given value into the equation immediately and simplify to a one-variable equation. Then solve step by step using inverse operations (undo addition/subtraction first, then multiplication/division). Finally, check by plugging your result back into the original context to ensure the total (like money or distance) matches the problem description.
Hints
Use the given equation
You are given an equation that relates bracelets () and necklaces () to the total money collected. Focus on that equation: .
Substitute the known value
You are told that 4 necklaces are sold. Replace in the equation with 4, then simplify.
Solve the one-variable equation
After substituting , you will have an equation in terms of only. Use inverse operations (undo addition, then undo multiplication) to solve for .
Desmos Guide
Enter the equation with the known value of y
In Desmos, type 2x + 5(4) = 50 (this substitutes 4 for ). Desmos will treat this as an equation in only.
Solve or inspect the solution for x
Click on the equation or use the Desmos solver feature (if available) to find the value of that makes the equation true. The -value you see is the number of bracelets sold.
Step-by-step Explanation
Substitute the given number of necklaces
We are told that necklaces are sold. Substitute into the equation:
This replaces with the known value so the equation now has only one variable, .
Simplify the equation
Now simplify and rewrite the equation:
So the equation becomes
Isolate the term with
To isolate the term, subtract 20 from both sides of the equation:
Solve for and interpret the result
Now divide both sides by 2 to solve for :
So, 15 bracelets were sold.