After factoring out $(x-3)$, you will have something like $(x-3)(\text{fraction}) = 5$. Carefully subtract $\tfrac16$ from $\tfrac23$ using a common denominator.

Once you have a single fraction multiplying $(x-3)$, think about what you can multiply both sides by to eliminate the fraction.

When you get an equation like $x - 3 = \text{number}$, what operation will isolate $x$?

In one line, type y = (2/3)(x-3) - (1/6)(x-3). In another line, type y = 5. This graphs the left side and right side of the equation as two functions.

Look for the point where the two graphs intersect. Click on the intersection; the x-coordinate of this point is the solution to the equation.

Notice that both terms on the left share the factor $(x-3)$:

So the equation becomes

Find $\tfrac23 - \tfrac16$ using a common denominator of $6$:

• $\tfrac23 = \tfrac46$
• $\tfrac16 = \tfrac16$

So

Now the equation is

To get rid of the $\tfrac12$, multiply both sides of the equation by $2$:

which simplifies to

Now solve the simple linear equation:

Add $3$ to both sides:

So the value of $x$ that satisfies the equation is $13$.