A partial-fraction decomposition writes one fraction as a sum of simpler fractions. The cue is “for all values of ” with unknown constants in those fractions. Clear the denominators, then use a Desmos regression at allowed inputs to find the constants. Don’t sample where an original denominator is zero, even though the cleared polynomial identity can be used there.
Hints
- Hint 1
An excluded input makes a denominator zero. Both and appear below fractions here. Which two inputs must you leave out when testing the original equation?
- Hint 2
Multiply every term by the whole original denominator. Each fraction then becomes a polynomial term, giving you an equation that is easier to fit at several inputs.
- Hint 3
A polynomial of degree at most cannot have four distinct zeros unless it is zero everywhere. After clearing denominators, how many allowed inputs would establish that the two sides match?
Step-by-step
Approach 1: Clear denominators and fit the constants
Step 1Find the inputs you cannot sample
A denominator cannot be . The factors and rule out and , so neither input belongs in a regression on the original fractions.
- Step 2
Turn the fraction equation into a polynomial identity
Multiply both sides by , the common denominator. For instance, becomes :
The polynomials agree at every allowed input, so they are identical. Only the denominators were cleared; the constants still have to be found.
- Step 3
Use allowed inputs to find the requested constant
Name the original fraction . Type , then . All five inputs are allowed. Finally, type . The tells Desmos to fit the constants to those values. A cubic difference that is zero at more than three distinct inputs is zero everywhere. Under PARAMETERS, Desmos shows . That is the coefficient of , so Grid in 7.
Approach 2: Isolate coefficients in the cleared identity
Step 1Find the leading coefficient
In the cleared identity, only has an term. Its coefficient, meaning the number multiplying , must match the on the left:
- Step 2
Evaluate the numerator at a useful input
The cleared identity is a polynomial identity, so you may use there even though the original fractions are undefined there. Name the numerator . Type and ; Desmos shows .
- Step 3
Use that input to isolate
At , every term in the cleared identity except contains and becomes . Substitute :
Divide by :
- Step 4
Identify the contributions
The coefficient of is the number multiplying . In , the pieces are . Each of and contributes . The term contributes none, so the right-side coefficient is .
- Step 5
Match coefficients to find
The left-side coefficient is . Match it to the right-side coefficient:
Substitute and :
Combine the numbers:
Add :
So the coefficient asked for is . Grid in 7.
Lessons that teach this
- SAT Advanced AlgebraAdvancedCoreUse polynomial identities, factors, and unknown coefficients
- SAT Advanced AlgebraIntermediateRewrite rational expressions and preserve restrictions
- DesmosAdvancedCoreFind constants in equivalent expressions
- DesmosAdvancedFactor, root, and remainder tests
- DesmosIntermediateRestrictions, piecewise functions, and rational expressions