A linear model describes a straight trend using a slope, the height gained per week, and an intercept, the height at week . For measured points on a scatterplot, a Desmos table and linear regression can estimate both numbers. Compare both with the choices: a line can have the right growth rate but the wrong starting height.
Hints
- Hint 1
Each dot pairs an input with an output. Put weeks in and the height measured at that week in . Keep the two coordinates of each dot in the same table row.
- Hint 2
A linear regression fits a straight line to all the points. Type after entering the table; the tells Desmos to find values for and .
- Hint 3
In , the slope is centimeters gained per week, while is the height at week . Which choice matches both fitted values?
Step-by-step
Fit the plotted points in Desmos
Step 1Pair each week with its measured height
Read the axes first: weeks are the input, and height is the output. Enter the plotted dots as approximate pairs in a Desmos table, with weeks in and heights in . For example, the leftmost dot is about and the rightmost is about . Desmos shows each week's height beside that week.
- Step 2
Fit a line to the measurements
Type . The regression fits a line to the overall trend instead of requiring every measured dot to lie on it. Under PARAMETERS, Desmos shows and . So the fitted line gains about centimeters per week and starts at about centimeters.
- Step 3
Match both parts of the model
The closest offered slope is , and the closest starting height is . Match both the slope and the starting height to the scatterplot. Matching only the slope would miss that a line starting at centimeters is too high at week . The vine's height is best modeled by . Choice B.