In a shifted exponential function, inputs where one is three times the other point to a power rule: the exponential part at the larger input is the cube of the part at the smaller input. Cube the powered part, not the entire output. Name that part, subtract the two outputs to remove the shared shift, and use a Desmos regression to find its value.
Hints
- Hint 1
A point on a function's graph means . Use each point's first coordinate as the input to write an equation for its output.
- Hint 2
The power rule gives . The stays outside the power, so it isn't cubed along with .
- Hint 3
Both point equations contain the same . Subtract one equation from the other to remove it, then solve for the positive value of .
Step-by-step
Cube the exponential part
Step 1Turn the points into equations
A point on the graph means the input gives the output . Substitute each given input into :
- Step 2
Name the part that gets cubed
Let . Tripling the exponent cubes the power because . The is outside that power, so the equations become:
- Step 3
Remove the shared shift
Subtract the first equation from the second, so the two copies of cancel:
- Step 4
Find the positive exponential value
Since , its power must be positive. Type in Desmos, using for . The tells Desmos to fit that unknown; under PARAMETERS, it shows . So , which is possible with and .
- Step 5
Recover the requested shift
The problem asks for , not . From , add to both sides:
Subtract :
Add below the regression in Desmos. It displays , so a possible value of is . Choice D.