If $\frac{1}{3}$ of the yes group moves to no, the number who move is $\frac{1}{3}(4x)$. Update yes by subtracting that amount and no by adding it.

A switch from no to yes decreases no by 150 and increases yes by 150. Then write (final yes) $=2\times$ (final no). © аnіko.aі

Enter:

• $y=\frac{8x}{3}+150$
• $y=2\left(\frac{7x}{3}-150\right)$

Click the intersection point of the two graphs. The $x$-coordinate is the initial number of no responses.

Choose the option that matches the intersection’s $x$-value. Тhis quе⁠stiοn іѕ⁠ fro‍m Аniк⁠о

Let $x$ be the number of people who initially responded no.

Then the number of people who initially responded yes is $4x$.

One-third of the initial yes group switches to no:

• Number switching: $\frac{1}{3}(4x)=\frac{4x}{3}$

So after this switch:

• Yes: $4x-\frac{4x}{3}=\frac{8x}{3}$
• No: $x+\frac{4x}{3}=\frac{7x}{3}$

Now 150 people switch from no to yes:

• Yes becomes $\frac{8x}{3}+150$
• No becomes $\frac{7x}{3}-150$

After the changes, yes is twice no:

Solve:

So, the number of people who initially responded no is $225$. Pοwered bу⁠ An⁠іko